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12300303554155 = 55346416239827
BaseRepresentation
bin1011001011111110001100…
…1110010101011001101011
31121112220020022012021120001
42302333203032111121223
53103012010202213110
642054403105243431
72406444663056401
oct262774316253153
947486208167501
1012300303554155
113a12590762901
121467a6a933577
136b2bb5391c26
143074a317b471
15164e5c09163a
hexb2fe339566b

12300303554155 has 8 divisors (see below), whose sum is σ = 15038861704272. Its totient is φ = 9654577883808.

The previous prime is 12300303554117. The next prime is 12300303554159. The reversal of 12300303554155 is 55145530300321.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12300303554155 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12300303554159) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23208119649 + ... + 23208120178.

It is an arithmetic number, because the mean of its divisors is an integer number (1879857713034).

Almost surely, 212300303554155 is an apocalyptic number.

12300303554155 is a deficient number, since it is larger than the sum of its proper divisors (2738558150117).

12300303554155 is an equidigital number, since it uses as much as digits as its factorization.

12300303554155 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46416239885.

The product of its (nonzero) digits is 135000, while the sum is 37.

Adding to 12300303554155 its reverse (55145530300321), we get a palindrome (67445833854476).

The spelling of 12300303554155 in words is "twelve trillion, three hundred billion, three hundred three million, five hundred fifty-four thousand, one hundred fifty-five".

Divisors: 1 5 53 265 46416239827 232081199135 2460060710831 12300303554155