Base | Representation |
---|---|
bin | 111001010001110100… |
… | …0001011001011010010 |
3 | 102202111101021222010011 |
4 | 1302203220023023102 |
5 | 4003403100131114 |
6 | 132301333025134 |
7 | 11613106213315 |
oct | 1624350131322 |
9 | 382441258104 |
10 | 123004302034 |
11 | 481907a3769 |
12 | 1ba09a851aa |
13 | b7a3746a93 |
14 | 5d4c34c97c |
15 | 32edae91c4 |
hex | 1ca3a0b2d2 |
123004302034 has 4 divisors (see below), whose sum is σ = 184506453054. Its totient is φ = 61502151016.
The previous prime is 123004301993. The next prime is 123004302037. The reversal of 123004302034 is 430203400321.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 430203400321 = 863 ⋅498497567.
It can be written as a sum of positive squares in only one way, i.e., 98719754809 + 24284547225 = 314197^2 + 155835^2 .
It is a junction number, because it is equal to n+sod(n) for n = 123004301996 and 123004302014.
It is not an unprimeable number, because it can be changed into a prime (123004302037) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30751075507 + ... + 30751075510.
Almost surely, 2123004302034 is an apocalyptic number.
123004302034 is a deficient number, since it is larger than the sum of its proper divisors (61502151020).
123004302034 is an equidigital number, since it uses as much as digits as its factorization.
123004302034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61502151019.
The product of its (nonzero) digits is 1728, while the sum is 22.
Adding to 123004302034 its reverse (430203400321), we get a palindrome (553207702355).
The spelling of 123004302034 in words is "one hundred twenty-three billion, four million, three hundred two thousand, thirty-four".
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