Base | Representation |
---|---|
bin | 1011001100000000110011… |
… | …0011010000111111110111 |
3 | 1121112222000220202100100121 |
4 | 2303000030303100333313 |
5 | 3103014422240220203 |
6 | 42055000224152411 |
7 | 2406501163113505 |
oct | 263001463207767 |
9 | 47488026670317 |
10 | 12301001101303 |
11 | 3a12909487352 |
12 | 1468024468707 |
13 | 6b2c96a52a15 |
14 | 30752ba77675 |
15 | 164e9d42c0bd |
hex | b300ccd0ff7 |
12301001101303 has 2 divisors, whose sum is σ = 12301001101304. Its totient is φ = 12301001101302.
The previous prime is 12301001101261. The next prime is 12301001101313. The reversal of 12301001101303 is 30310110010321.
It is a strong prime.
It is an emirp because it is prime and its reverse (30310110010321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12301001101303 - 225 = 12300967546871 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12301001101313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6150500550651 + 6150500550652.
It is an arithmetic number, because the mean of its divisors is an integer number (6150500550652).
Almost surely, 212301001101303 is an apocalyptic number.
12301001101303 is a deficient number, since it is larger than the sum of its proper divisors (1).
12301001101303 is an equidigital number, since it uses as much as digits as its factorization.
12301001101303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 12301001101303 its reverse (30310110010321), we get a palindrome (42611111111624).
The spelling of 12301001101303 in words is "twelve trillion, three hundred one billion, one million, one hundred one thousand, three hundred three".
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