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12301002013 = 32063383651
BaseRepresentation
bin10110111010011001…
…00110010100011101
31011202021111122111011
423131030212110131
5200143024031023
65352341055221
7613554535426
oct133514462435
934667448434
1012301002013
11524265a973
1224736b7511
131210623721
148499b264d
154bedcb50d
hex2dd32651d

12301002013 has 4 divisors (see below), whose sum is σ = 12301417728. Its totient is φ = 12300586300.

The previous prime is 12301002011. The next prime is 12301002019. The reversal of 12301002013 is 31020010321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12301002013 - 21 = 12301002011 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12301001984 and 12301002002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12301002011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 159763 + ... + 223888.

It is an arithmetic number, because the mean of its divisors is an integer number (3075354432).

Almost surely, 212301002013 is an apocalyptic number.

It is an amenable number.

12301002013 is a deficient number, since it is larger than the sum of its proper divisors (415715).

12301002013 is an equidigital number, since it uses as much as digits as its factorization.

12301002013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 415714.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 12301002013 its reverse (31020010321), we get a palindrome (43321012334).

The spelling of 12301002013 in words is "twelve billion, three hundred one million, two thousand, thirteen".

Divisors: 1 32063 383651 12301002013