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123011343113 is a prime number
BaseRepresentation
bin111001010010000001…
…1000010001100001001
3102202111212112200122212
41302210003002030021
54003411400434423
6132302143554505
711613223110251
oct1624403021411
9382455480585
10123011343113
114819477283a
121ba102bba35
13b7a50408b9
145d4d262961
1532ee53a578
hex1ca40c2309

123011343113 has 2 divisors, whose sum is σ = 123011343114. Its totient is φ = 123011343112.

The previous prime is 123011343107. The next prime is 123011343157. The reversal of 123011343113 is 311343110321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 84301961104 + 38709382009 = 290348^2 + 196747^2 .

It is an emirp because it is prime and its reverse (311343110321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 123011343113 - 214 = 123011326729 is a prime.

It is not a weakly prime, because it can be changed into another prime (123011343163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61505671556 + 61505671557.

It is an arithmetic number, because the mean of its divisors is an integer number (61505671557).

Almost surely, 2123011343113 is an apocalyptic number.

It is an amenable number.

123011343113 is a deficient number, since it is larger than the sum of its proper divisors (1).

123011343113 is an equidigital number, since it uses as much as digits as its factorization.

123011343113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 123011343113 its reverse (311343110321), we get a palindrome (434354453434).

The spelling of 123011343113 in words is "one hundred twenty-three billion, eleven million, three hundred forty-three thousand, one hundred thirteen".