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123012013013 is a prime number
BaseRepresentation
bin111001010010000010…
…1100101101111010101
3102202111220210201120222
41302210011211233111
54003412033404023
6132302210204125
711613231600311
oct1624405455725
9382456721528
10123012013013
114819509007a
121ba10583645
13b7a52167a6
145d4d398b41
1532ee61dcc8
hex1ca4165bd5

123012013013 has 2 divisors, whose sum is σ = 123012013014. Its totient is φ = 123012013012.

The previous prime is 123012013009. The next prime is 123012013081. The reversal of 123012013013 is 310310210321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 61940258884 + 61071754129 = 248878^2 + 247127^2 .

It is an emirp because it is prime and its reverse (310310210321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 123012013013 - 22 = 123012013009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 123012012982 and 123012013000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123012013093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61506006506 + 61506006507.

It is an arithmetic number, because the mean of its divisors is an integer number (61506006507).

Almost surely, 2123012013013 is an apocalyptic number.

It is an amenable number.

123012013013 is a deficient number, since it is larger than the sum of its proper divisors (1).

123012013013 is an equidigital number, since it uses as much as digits as its factorization.

123012013013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 123012013013 its reverse (310310210321), we get a palindrome (433322223334).

The spelling of 123012013013 in words is "one hundred twenty-three billion, twelve million, thirteen thousand, thirteen".