123012240001307 has 2 divisors, whose sum is σ = 123012240001308. Its totient is φ = 123012240001306.

The previous prime is 123012240001207. The next prime is 123012240001309. The reversal of 123012240001307 is 703100042210321.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 123012240001307 - 2³⁰ = 123011166259483 is a prime.

It is a super-2 number, since 2×123012240001307² (a number of 29 digits) contains 22 as substring.

Together with 123012240001309, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (123012240001309) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61506120000653 + 61506120000654.

It is an arithmetic number, because the mean of its divisors is an integer number (61506120000654).

Almost surely, 2^{123012240001307} is an apocalyptic number.

123012240001307 is a deficient number, since it is larger than the sum of its proper divisors (1).

123012240001307 is an equidigital number, since it uses as much as digits as its factorization.

123012240001307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 26.

Adding to 123012240001307 its reverse (703100042210321), we get a palindrome (826112282211628).

The spelling of 123012240001307 in words is "one hundred twenty-three trillion, twelve billion, two hundred forty million, one thousand, three hundred seven".