Base | Representation |
---|---|
bin | 1011001100000001111111… |
… | …1100100101001010101000 |
3 | 1121112222212022011110021120 |
4 | 2303000133330211022220 |
5 | 3103021102002412222 |
6 | 42055052140535240 |
7 | 2406512143256100 |
oct | 263003774451250 |
9 | 47488768143246 |
10 | 12301322310312 |
11 | 3a12a63827442 |
12 | 14680b3b51520 |
13 | 6b3018468319 |
14 | 30755c5ac200 |
15 | 164ebb72a15c |
hex | b301ff252a8 |
12301322310312 has 96 divisors (see below), whose sum is σ = 35785553313600. Its totient is φ = 3513553376256.
The previous prime is 12301322310269. The next prime is 12301322310353. The reversal of 12301322310312 is 21301322310321.
It is a super-4 number, since 4×123013223103124 (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2076333 + ... + 5377155.
It is an arithmetic number, because the mean of its divisors is an integer number (372766180350).
Almost surely, 212301322310312 is an apocalyptic number.
12301322310312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 12301322310312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17892776656800).
12301322310312 is an abundant number, since it is smaller than the sum of its proper divisors (23484231003288).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12301322310312 is a wasteful number, since it uses less digits than its factorization.
12301322310312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3304015 (or 3304004 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 12301322310312 its reverse (21301322310321), we get a palindrome (33602644620633).
Subtracting 12301322310312 from its reverse (21301322310321), we obtain a palindrome (9000000000009).
The spelling of 12301322310312 in words is "twelve trillion, three hundred one billion, three hundred twenty-two million, three hundred ten thousand, three hundred twelve".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •