Base | Representation |
---|---|
bin | 11011111110000101000100… |
… | …110001011000100111110111 |
3 | 121010112221212020011010211111 |
4 | 123332011010301120213313 |
5 | 112110422230400340320 |
6 | 1113343311353215451 |
7 | 34624263356461516 |
oct | 3376050461304767 |
9 | 533487766133744 |
10 | 123013312121335 |
11 | 3621771a818759 |
12 | 11968979401587 |
13 | 538414abb163c |
14 | 2253c39d3c67d |
15 | e34cd2901a5a |
hex | 6fe144c589f7 |
123013312121335 has 8 divisors (see below), whose sum is σ = 147638043052560. Its totient is φ = 98395937359104.
The previous prime is 123013312121267. The next prime is 123013312121341. The reversal of 123013312121335 is 533121213310321.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 123013312121335 - 239 = 122463556307447 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 123013312121297 and 123013312121306.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1839005457 + ... + 1839072346.
It is an arithmetic number, because the mean of its divisors is an integer number (18454755381570).
Almost surely, 2123013312121335 is an apocalyptic number.
123013312121335 is a deficient number, since it is larger than the sum of its proper divisors (24624730931225).
123013312121335 is an equidigital number, since it uses as much as digits as its factorization.
123013312121335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3678084497.
The product of its (nonzero) digits is 9720, while the sum is 31.
Adding to 123013312121335 its reverse (533121213310321), we get a palindrome (656134525431656).
The spelling of 123013312121335 in words is "one hundred twenty-three trillion, thirteen billion, three hundred twelve million, one hundred twenty-one thousand, three hundred thirty-five".
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