12301393125 has 80 divisors (see below), whose sum is σ = 23526968960. Its totient is φ = 5598720000.

The previous prime is 12301393099. The next prime is 12301393127. The reversal of 12301393125 is 52139310321.

It is not a de Polignac number, because 12301393125 - 2¹³ = 12301384933 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12301393092 and 12301393101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12301393127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 3161181 + ... + 3165069.

It is an arithmetic number, because the mean of its divisors is an integer number (294087112).

Almost surely, 2^12301393125 is an apocalyptic number.

12301393125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

12301393125 is a deficient number, since it is larger than the sum of its proper divisors (11225575835).

12301393125 is an equidigital number, since it uses as much as digits as its factorization.

12301393125 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4160 (or 4145 counting only the distinct ones).

The product of its (nonzero) digits is 4860, while the sum is 30.

The spelling of 12301393125 in words is "twelve billion, three hundred one million, three hundred ninety-three thousand, one hundred twenty-five".