Base | Representation |
---|---|
bin | 111001010010000110… |
… | …1001110011000000111 |
3 | 102202112001120102002001 |
4 | 1302210031032120013 |
5 | 4003413041430341 |
6 | 132302321130131 |
7 | 11613254604415 |
oct | 1624415163007 |
9 | 382461512061 |
10 | 123014014471 |
11 | 48196227877 |
12 | 1ba11189947 |
13 | b7a576779a |
14 | 5d4d75a2b5 |
15 | 32ee8b6d31 |
hex | 1ca434e607 |
123014014471 has 2 divisors, whose sum is σ = 123014014472. Its totient is φ = 123014014470.
The previous prime is 123014014457. The next prime is 123014014477. The reversal of 123014014471 is 174410410321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123014014471 - 215 = 123013981703 is a prime.
It is a super-3 number, since 3×1230140144713 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123014014477) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61507007235 + 61507007236.
It is an arithmetic number, because the mean of its divisors is an integer number (61507007236).
Almost surely, 2123014014471 is an apocalyptic number.
123014014471 is a deficient number, since it is larger than the sum of its proper divisors (1).
123014014471 is an equidigital number, since it uses as much as digits as its factorization.
123014014471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2688, while the sum is 28.
Adding to 123014014471 its reverse (174410410321), we get a palindrome (297424424792).
The spelling of 123014014471 in words is "one hundred twenty-three billion, fourteen million, fourteen thousand, four hundred seventy-one".
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