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123014014471 is a prime number
BaseRepresentation
bin111001010010000110…
…1001110011000000111
3102202112001120102002001
41302210031032120013
54003413041430341
6132302321130131
711613254604415
oct1624415163007
9382461512061
10123014014471
1148196227877
121ba11189947
13b7a576779a
145d4d75a2b5
1532ee8b6d31
hex1ca434e607

123014014471 has 2 divisors, whose sum is σ = 123014014472. Its totient is φ = 123014014470.

The previous prime is 123014014457. The next prime is 123014014477. The reversal of 123014014471 is 174410410321.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 123014014471 - 215 = 123013981703 is a prime.

It is a super-3 number, since 3×1230140144713 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123014014477) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61507007235 + 61507007236.

It is an arithmetic number, because the mean of its divisors is an integer number (61507007236).

Almost surely, 2123014014471 is an apocalyptic number.

123014014471 is a deficient number, since it is larger than the sum of its proper divisors (1).

123014014471 is an equidigital number, since it uses as much as digits as its factorization.

123014014471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2688, while the sum is 28.

Adding to 123014014471 its reverse (174410410321), we get a palindrome (297424424792).

The spelling of 123014014471 in words is "one hundred twenty-three billion, fourteen million, fourteen thousand, four hundred seventy-one".