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123014422019 is a prime number
BaseRepresentation
bin111001010010000111…
…0110001111000000011
3102202112002100010010102
41302210032301320003
54003413143001034
6132302333553015
711613261222536
oct1624416617003
9382462303112
10123014422019
1148196485a95
121ba1134576b
13b7a587b138
145d4d824a1d
1532ee94797e
hex1ca43b1e03

123014422019 has 2 divisors, whose sum is σ = 123014422020. Its totient is φ = 123014422018.

The previous prime is 123014421989. The next prime is 123014422021. The reversal of 123014422019 is 910224410321.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 123014422019 - 232 = 118719454723 is a prime.

It is a super-2 number, since 2×1230144220192 (a number of 23 digits) contains 22 as substring.

Together with 123014422021, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 123014421982 and 123014422000.

It is not a weakly prime, because it can be changed into another prime (123014422039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61507211009 + 61507211010.

It is an arithmetic number, because the mean of its divisors is an integer number (61507211010).

Almost surely, 2123014422019 is an apocalyptic number.

123014422019 is a deficient number, since it is larger than the sum of its proper divisors (1).

123014422019 is an equidigital number, since it uses as much as digits as its factorization.

123014422019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 29.

The spelling of 123014422019 in words is "one hundred twenty-three billion, fourteen million, four hundred twenty-two thousand, nineteen".