Base | Representation |
---|---|
bin | 1011001100000100101000… |
… | …1101010111111000011111 |
3 | 1121120001200201100200022121 |
4 | 2303001022031113320133 |
5 | 3103024030011333143 |
6 | 42055250350123411 |
7 | 2406535543122025 |
oct | 263011215277037 |
9 | 47501621320277 |
10 | 12302031355423 |
11 | 3a13297a94537 |
12 | 14682714b0567 |
13 | 6b30cc323744 |
14 | 3075c881c715 |
15 | 16500dad77ed |
hex | b304a357e1f |
12302031355423 has 2 divisors, whose sum is σ = 12302031355424. Its totient is φ = 12302031355422.
The previous prime is 12302031355351. The next prime is 12302031355441. The reversal of 12302031355423 is 32455313020321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12302031355423 - 213 = 12302031347231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12302031350423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6151015677711 + 6151015677712.
It is an arithmetic number, because the mean of its divisors is an integer number (6151015677712).
Almost surely, 212302031355423 is an apocalyptic number.
12302031355423 is a deficient number, since it is larger than the sum of its proper divisors (1).
12302031355423 is an equidigital number, since it uses as much as digits as its factorization.
12302031355423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64800, while the sum is 34.
Adding to 12302031355423 its reverse (32455313020321), we get a palindrome (44757344375744).
The spelling of 12302031355423 in words is "twelve trillion, three hundred two billion, thirty-one million, three hundred fifty-five thousand, four hundred twenty-three".
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