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12302232111119 is a prime number
BaseRepresentation
bin1011001100000101011000…
…1011001100100000001111
31121120002012201010010100202
42303001112023030200033
53103024432410023434
642055322321044115
72406543531404426
oct263012613144017
947502181103322
1012302232111119
113a13390343235
12146830878663b
136b3131ab39b2
1430760735a2bd
15165021540a7e
hexb30562cc80f

12302232111119 has 2 divisors, whose sum is σ = 12302232111120. Its totient is φ = 12302232111118.

The previous prime is 12302232111079. The next prime is 12302232111121. The reversal of 12302232111119 is 91111123220321.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12302232111119 - 28 = 12302232110863 is a prime.

It is a super-2 number, since 2×123022321111192 (a number of 27 digits) contains 22 as substring.

Together with 12302232111121, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12302232111091 and 12302232111100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12302232111019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6151116055559 + 6151116055560.

It is an arithmetic number, because the mean of its divisors is an integer number (6151116055560).

Almost surely, 212302232111119 is an apocalyptic number.

12302232111119 is a deficient number, since it is larger than the sum of its proper divisors (1).

12302232111119 is an equidigital number, since it uses as much as digits as its factorization.

12302232111119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 29.

The spelling of 12302232111119 in words is "twelve trillion, three hundred two billion, two hundred thirty-two million, one hundred eleven thousand, one hundred nineteen".