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12302342017 = 71757477431
BaseRepresentation
bin10110111010100011…
…01101011110000001
31011202101000201121221
423131101231132001
5200143344421032
65352425515041
7613602116230
oct133521553601
934671021557
1012302342017
115243395709
122474042a81
1312109a2624
14849c40b17
154c0093597
hex2dd46d781

12302342017 has 4 divisors (see below), whose sum is σ = 14059819456. Its totient is φ = 10544864580.

The previous prime is 12302341967. The next prime is 12302342057. The reversal of 12302342017 is 71024320321.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12302342017 - 27 = 12302341889 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12302341982 and 12302342000.

It is not an unprimeable number, because it can be changed into a prime (12302342057) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 878738709 + ... + 878738722.

It is an arithmetic number, because the mean of its divisors is an integer number (3514954864).

Almost surely, 212302342017 is an apocalyptic number.

It is an amenable number.

12302342017 is a deficient number, since it is larger than the sum of its proper divisors (1757477439).

12302342017 is an equidigital number, since it uses as much as digits as its factorization.

12302342017 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1757477438.

The product of its (nonzero) digits is 2016, while the sum is 25.

Adding to 12302342017 its reverse (71024320321), we get a palindrome (83326662338).

The spelling of 12302342017 in words is "twelve billion, three hundred two million, three hundred forty-two thousand, seventeen".

Divisors: 1 7 1757477431 12302342017