Base | Representation |
---|---|
bin | 10001111001111101011… |
… | …100100000011010101111 |
3 | 11100122001020111020211021 |
4 | 101321331130200122233 |
5 | 130124443102141341 |
6 | 2341133513035011 |
7 | 154620035144332 |
oct | 21717534403257 |
9 | 4318036436737 |
10 | 1230465271471 |
11 | 4349236274a7 |
12 | 17a5803b5a67 |
13 | 8c056195867 |
14 | 437aa688619 |
15 | 220195bc9d1 |
hex | 11e7d7206af |
1230465271471 has 2 divisors, whose sum is σ = 1230465271472. Its totient is φ = 1230465271470.
The previous prime is 1230465271459. The next prime is 1230465271517. The reversal of 1230465271471 is 1741725640321.
It is a weak prime.
It is an emirp because it is prime and its reverse (1741725640321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1230465271471 - 233 = 1221875336879 is a prime.
It is a super-3 number, since 3×12304652714713 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1230465271421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615232635735 + 615232635736.
It is an arithmetic number, because the mean of its divisors is an integer number (615232635736).
Almost surely, 21230465271471 is an apocalyptic number.
1230465271471 is a deficient number, since it is larger than the sum of its proper divisors (1).
1230465271471 is an equidigital number, since it uses as much as digits as its factorization.
1230465271471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 282240, while the sum is 43.
The spelling of 1230465271471 in words is "one trillion, two hundred thirty billion, four hundred sixty-five million, two hundred seventy-one thousand, four hundred seventy-one".
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