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1231101021312 = 273217373534813
BaseRepresentation
bin10001111010100011010…
…101101100110010000000
311100200200112202200122200
4101322203111230302000
5130132243330140222
62341320543233200
7154641555010401
oct21724325546200
94320615680580
101231101021312
1143511a482798
1217a7192a8800
138c127aca5b6
144382ac999a8
15220552eceac
hex11ea356cc80

1231101021312 has 384 divisors, whose sum is σ = 3864105563760. Its totient is φ = 374646767616.

The previous prime is 1231101021259. The next prime is 1231101021317. The reversal of 1231101021312 is 2131201011321.

1231101021312 is a `hidden beast` number, since 1 + 231 + 101 + 0 + 21 + 312 = 666.

It can be written as a sum of positive squares in 8 ways, for example, as 1104062953536 + 127038067776 = 1050744^2 + 356424^2 .

It is a tau number, because it is divible by the number of its divisors (384).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (1231101021317) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 255784218 + ... + 255789030.

Almost surely, 21231101021312 is an apocalyptic number.

1231101021312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1231101021312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1932052781880).

1231101021312 is an abundant number, since it is smaller than the sum of its proper divisors (2633004542448).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1231101021312 is a wasteful number, since it uses less digits than its factorization.

1231101021312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5240 (or 5225 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 1231101021312 its reverse (2131201011321), we get a palindrome (3362302032633).

Subtracting 1231101021312 from its reverse (2131201011321), we obtain a palindrome (900099990009).

The spelling of 1231101021312 in words is "one trillion, two hundred thirty-one billion, one hundred one million, twenty-one thousand, three hundred twelve".