123111311118335 has 4 divisors (see below), whose sum is σ = 147733573342008. Its totient is φ = 98489048894664.

The previous prime is 123111311118269. The next prime is 123111311118371. The reversal of 123111311118335 is 533811113111321.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 123111311118335 - 2¹⁶ = 123111311052799 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 123111311118295 and 123111311118304.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12311131111829 + ... + 12311131111838.

It is an arithmetic number, because the mean of its divisors is an integer number (36933393335502).

Almost surely, 2^{123111311118335} is an apocalyptic number.

123111311118335 is a deficient number, since it is larger than the sum of its proper divisors (24622262223673).

123111311118335 is an equidigital number, since it uses as much as digits as its factorization.

123111311118335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24622262223672.

The product of its digits is 6480, while the sum is 35.

Adding to 123111311118335 its reverse (533811113111321), we get a palindrome (656922424229656).

The spelling of 123111311118335 in words is "one hundred twenty-three trillion, one hundred eleven billion, three hundred eleven million, one hundred eighteen thousand, three hundred thirty-five".