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123113101023133 = 134325121816409
BaseRepresentation
bin11011111111100010000000…
…101001110101011110011101
3121010220111102200120120210021
4123333202000221311132131
5112114041112330220013
61113501213335512141
734634425261240414
oct3377420051653635
9533814380516707
10123113101023133
1136255a77a80631
1211984188528651
135390691a4c3b0
1422589c4d2c47b
15e376c333da8d
hex6ff880a7579d

123113101023133 has 12 divisors (see below), whose sum is σ = 135738378497820. Its totient is φ = 111000005194176.

The previous prime is 123113101023053. The next prime is 123113101023247. The reversal of 123113101023133 is 331320101311321.

It can be written as a sum of positive squares in 2 ways, for example, as 13180769864089 + 109932331159044 = 3630533^2 + 10484862^2 .

It is not a de Polignac number, because 123113101023133 - 29 = 123113101022621 is a prime.

It is a super-2 number, since 2×1231131010231332 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 123113101023098 and 123113101023107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (123113101029133) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2560884168 + ... + 2560932241.

It is an arithmetic number, because the mean of its divisors is an integer number (11311531541485).

Almost surely, 2123113101023133 is an apocalyptic number.

123113101023133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

123113101023133 is a deficient number, since it is larger than the sum of its proper divisors (12625277474687).

123113101023133 is an equidigital number, since it uses as much as digits as its factorization.

123113101023133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5121816508 (or 5121816465 counting only the distinct ones).

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 123113101023133 its reverse (331320101311321), we get a palindrome (454433202334454).

The spelling of 123113101023133 in words is "one hundred twenty-three trillion, one hundred thirteen billion, one hundred one million, twenty-three thousand, one hundred thirty-three".

Divisors: 1 13 43 559 1849 24037 5121816409 66583613317 220238105587 2863095372631 9470238540241 123113101023133