Base | Representation |
---|---|
bin | 10110111011110100… |
… | …10111100101111001 |
3 | 1011210010002020001122 |
4 | 23131322113211321 |
5 | 200204112002223 |
6 | 5353450155025 |
7 | 614061530045 |
oct | 133572274571 |
9 | 34703066048 |
10 | 12313000313 |
11 | 5249405419 |
12 | 2477722a75 |
13 | 1212c64a03 |
14 | 84b417025 |
15 | 4c0e9b5c8 |
hex | 2dde97979 |
12313000313 has 2 divisors, whose sum is σ = 12313000314. Its totient is φ = 12313000312.
The previous prime is 12313000307. The next prime is 12313000319. The reversal of 12313000313 is 31300031321.
It is a balanced prime because it is at equal distance from previous prime (12313000307) and next prime (12313000319).
It can be written as a sum of positive squares in only one way, i.e., 9422002489 + 2890997824 = 97067^2 + 53768^2 .
It is a cyclic number.
It is not a de Polignac number, because 12313000313 - 230 = 11239258489 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12313000291 and 12313000300.
It is not a weakly prime, because it can be changed into another prime (12313000319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156500156 + 6156500157.
It is an arithmetic number, because the mean of its divisors is an integer number (6156500157).
Almost surely, 212313000313 is an apocalyptic number.
It is an amenable number.
12313000313 is a deficient number, since it is larger than the sum of its proper divisors (1).
12313000313 is an equidigital number, since it uses as much as digits as its factorization.
12313000313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 12313000313 its reverse (31300031321), we get a palindrome (43613031634).
The spelling of 12313000313 in words is "twelve billion, three hundred thirteen million, three hundred thirteen", and thus it is an aban number.
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