Base | Representation |
---|---|
bin | 1011001100101101100111… |
… | …0001111010100101000011 |
3 | 1121121010002020021021122002 |
4 | 2303023121301322211003 |
5 | 3103214041140324303 |
6 | 42104310005334215 |
7 | 2410405235135615 |
oct | 263133161724503 |
9 | 47533066237562 |
10 | 12313030011203 |
11 | 3a17a214943a9 |
12 | 146a420a0736b |
13 | 6b4162b9a29c |
14 | 307d4d45cdb5 |
15 | 1654544ad788 |
hex | b32d9c7a943 |
12313030011203 has 2 divisors, whose sum is σ = 12313030011204. Its totient is φ = 12313030011202.
The previous prime is 12313030011169. The next prime is 12313030011211. The reversal of 12313030011203 is 30211003031321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12313030011203 - 234 = 12295850142019 is a prime.
It is a super-3 number, since 3×123130300112033 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (12313038011203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156515005601 + 6156515005602.
It is an arithmetic number, because the mean of its divisors is an integer number (6156515005602).
Almost surely, 212313030011203 is an apocalyptic number.
12313030011203 is a deficient number, since it is larger than the sum of its proper divisors (1).
12313030011203 is an equidigital number, since it uses as much as digits as its factorization.
12313030011203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 12313030011203 its reverse (30211003031321), we get a palindrome (42524033042524).
The spelling of 12313030011203 in words is "twelve trillion, three hundred thirteen billion, thirty million, eleven thousand, two hundred three".
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