Base | Representation |
---|---|
bin | 11100000000000101010011… |
… | …111010111010101111100111 |
3 | 121011001010021022000220110202 |
4 | 130000011103322322233213 |
5 | 112120201224314411403 |
6 | 1113530442450341115 |
7 | 34640236466554322 |
oct | 3400052372725747 |
9 | 534033238026422 |
10 | 123151005232103 |
11 | 36270058a05872 |
12 | 1198b5a658a79b |
13 | 5394122858804 |
14 | 225a77d0277b9 |
15 | e38690d40688 |
hex | 700153ebabe7 |
123151005232103 has 4 divisors (see below), whose sum is σ = 130395182010480. Its totient is φ = 115906828453728.
The previous prime is 123151005232037. The next prime is 123151005232133. The reversal of 123151005232103 is 301232500151321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 123151005232103 - 224 = 123150988454887 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (123151005232133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3622088389163 + ... + 3622088389196.
It is an arithmetic number, because the mean of its divisors is an integer number (32598795502620).
Almost surely, 2123151005232103 is an apocalyptic number.
123151005232103 is a deficient number, since it is larger than the sum of its proper divisors (7244176778377).
123151005232103 is an equidigital number, since it uses as much as digits as its factorization.
123151005232103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7244176778376.
The product of its (nonzero) digits is 5400, while the sum is 29.
Adding to 123151005232103 its reverse (301232500151321), we get a palindrome (424383505383424).
The spelling of 123151005232103 in words is "one hundred twenty-three trillion, one hundred fifty-one billion, five million, two hundred thirty-two thousand, one hundred three".
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