12315123131 has 2 divisors, whose sum is σ = 12315123132. Its totient is φ = 12315123130.

The previous prime is 12315123127. The next prime is 12315123133. The reversal of 12315123131 is 13132151321.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12315123131 - 2² = 12315123127 is a prime.

It is a super-2 number, since 2×12315123131² (a number of 21 digits) contains 22 as substring.

Together with 12315123133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12315123097 and 12315123106.

It is not a weakly prime, because it can be changed into another prime (12315123133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6157561565 + 6157561566.

It is an arithmetic number, because the mean of its divisors is an integer number (6157561566).

Almost surely, 2^12315123131 is an apocalyptic number.

12315123131 is a deficient number, since it is larger than the sum of its proper divisors (1).

12315123131 is an equidigital number, since it uses as much as digits as its factorization.

12315123131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 540, while the sum is 23.

Adding to 12315123131 its reverse (13132151321), we get a palindrome (25447274452).

The spelling of 12315123131 in words is "twelve billion, three hundred fifteen million, one hundred twenty-three thousand, one hundred thirty-one".