12315210304131 has 32 divisors (see below), whose sum is σ = 20851680153600. Its totient is φ = 7037084010240.

The previous prime is 12315210304073. The next prime is 12315210304181. The reversal of 12315210304131 is 13140301251321.

12315210304131 is a `hidden beast` number, since 1 + 2 + 3 + 1 + 5 + 210 + 30 + 413 + 1 = 666.

It is not a de Polignac number, because 12315210304131 - 2¹⁰ = 12315210303107 is a prime.

It is a super-3 number, since 3×12315210304131³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 12315210304095 and 12315210304104.

It is not an unprimeable number, because it can be changed into a prime (12315210304181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6805966 + ... + 8423276.

It is an arithmetic number, because the mean of its divisors is an integer number (651615004800).

Almost surely, 2^{12315210304131} is an apocalyptic number.

12315210304131 is a deficient number, since it is larger than the sum of its proper divisors (8536469849469).

12315210304131 is a wasteful number, since it uses less digits than its factorization.

12315210304131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1657616 (or 1657610 counting only the distinct ones).

The product of its (nonzero) digits is 2160, while the sum is 27.

Adding to 12315210304131 its reverse (13140301251321), we get a palindrome (25455511555452).

The spelling of 12315210304131 in words is "twelve trillion, three hundred fifteen billion, two hundred ten million, three hundred four thousand, one hundred thirty-one".