Search a number
-
+
12320201113 = 111120018283
BaseRepresentation
bin10110111100101011…
…10101100110011001
31011210121122001200221
423132111311212121
5200212432413423
65354304400041
7614206660453
oct133625654631
934717561627
1012320201113
1152524834a0
12247a016021
1312145b643c
1484c36d2d3
154c191ee5d
hex2de575999

12320201113 has 4 divisors (see below), whose sum is σ = 13440219408. Its totient is φ = 11200182820.

The previous prime is 12320201111. The next prime is 12320201119. The reversal of 12320201113 is 31110202321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12320201113 - 21 = 12320201111 is a prime.

It is a super-3 number, since 3×123202011133 (a number of 31 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (12320201111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 560009131 + ... + 560009152.

It is an arithmetic number, because the mean of its divisors is an integer number (3360054852).

Almost surely, 212320201113 is an apocalyptic number.

It is an amenable number.

12320201113 is a deficient number, since it is larger than the sum of its proper divisors (1120018295).

12320201113 is a wasteful number, since it uses less digits than its factorization.

12320201113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1120018294.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 12320201113 its reverse (31110202321), we get a palindrome (43430403434).

The spelling of 12320201113 in words is "twelve billion, three hundred twenty million, two hundred one thousand, one hundred thirteen".

Divisors: 1 11 1120018283 12320201113