Base | Representation |
---|---|
bin | 1011001101001000110011… |
… | …1101011011110111100111 |
3 | 1121121210221001121001011211 |
4 | 2303102030331123313213 |
5 | 3103324014231320403 |
6 | 42111514301412251 |
7 | 2411054201423446 |
oct | 263221475336747 |
9 | 47553831531154 |
10 | 12320331120103 |
11 | 3a200287aa5a6 |
12 | 146b919b6a087 |
13 | 6b4a5769b976 |
14 | 308442d9ad5d |
15 | 16573045506d |
hex | b348cf5bde7 |
12320331120103 has 2 divisors, whose sum is σ = 12320331120104. Its totient is φ = 12320331120102.
The previous prime is 12320331120037. The next prime is 12320331120113. The reversal of 12320331120103 is 30102113302321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12320331120103 - 225 = 12320297565671 is a prime.
It is a super-2 number, since 2×123203311201032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12320331120113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6160165560051 + 6160165560052.
It is an arithmetic number, because the mean of its divisors is an integer number (6160165560052).
Almost surely, 212320331120103 is an apocalyptic number.
12320331120103 is a deficient number, since it is larger than the sum of its proper divisors (1).
12320331120103 is an equidigital number, since it uses as much as digits as its factorization.
12320331120103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 12320331120103 its reverse (30102113302321), we get a palindrome (42422444422424).
The spelling of 12320331120103 in words is "twelve trillion, three hundred twenty billion, three hundred thirty-one million, one hundred twenty thousand, one hundred three".
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