Base | Representation |
---|---|
bin | 1011001101001000110011… |
… | …1101011011110111110001 |
3 | 1121121210221001121001012012 |
4 | 2303102030331123313301 |
5 | 3103324014231320423 |
6 | 42111514301412305 |
7 | 2411054201423462 |
oct | 263221475336761 |
9 | 47553831531165 |
10 | 12320331120113 |
11 | 3a200287aa605 |
12 | 146b919b6a095 |
13 | 6b4a5769b983 |
14 | 308442d9ad69 |
15 | 165730455078 |
hex | b348cf5bdf1 |
12320331120113 has 2 divisors, whose sum is σ = 12320331120114. Its totient is φ = 12320331120112.
The previous prime is 12320331120103. The next prime is 12320331120161. The reversal of 12320331120113 is 31102113302321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10480681062544 + 1839650057569 = 3237388^2 + 1356337^2 .
It is a cyclic number.
It is not a de Polignac number, because 12320331120113 - 212 = 12320331116017 is a prime.
It is not a weakly prime, because it can be changed into another prime (12320331120103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6160165560056 + 6160165560057.
It is an arithmetic number, because the mean of its divisors is an integer number (6160165560057).
Almost surely, 212320331120113 is an apocalyptic number.
It is an amenable number.
12320331120113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12320331120113 is an equidigital number, since it uses as much as digits as its factorization.
12320331120113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 12320331120113 its reverse (31102113302321), we get a palindrome (43422444422434).
The spelling of 12320331120113 in words is "twelve trillion, three hundred twenty billion, three hundred thirty-one million, one hundred twenty thousand, one hundred thirteen".
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