Base | Representation |
---|---|
bin | 10001111011011011010… |
… | …101010001101010000111 |
3 | 11100210010000102211000201 |
4 | 101323123111101222013 |
5 | 130141204322344221 |
6 | 2341554102151331 |
7 | 155004052620661 |
oct | 21733325215207 |
9 | 4323100384021 |
10 | 1232040434311 |
11 | 435561784675 |
12 | 17a93ba22547 |
13 | 8c24761358b |
14 | 438b9955531 |
15 | 220aca12891 |
hex | 11edb551a87 |
1232040434311 has 2 divisors, whose sum is σ = 1232040434312. Its totient is φ = 1232040434310.
The previous prime is 1232040434263. The next prime is 1232040434323. The reversal of 1232040434311 is 1134340402321.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1232040434311 - 217 = 1232040303239 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1232040434311.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1232040434351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616020217155 + 616020217156.
It is an arithmetic number, because the mean of its divisors is an integer number (616020217156).
Almost surely, 21232040434311 is an apocalyptic number.
1232040434311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1232040434311 is an equidigital number, since it uses as much as digits as its factorization.
1232040434311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 1232040434311 its reverse (1134340402321), we get a palindrome (2366380836632).
The spelling of 1232040434311 in words is "one trillion, two hundred thirty-two billion, forty million, four hundred thirty-four thousand, three hundred eleven".
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