Base | Representation |
---|---|
bin | 111001010111111100… |
… | …0111011010100011011 |
3 | 102210000201101112021122 |
4 | 1302233320323110123 |
5 | 4004313231120443 |
6 | 132334002155455 |
7 | 11621154614441 |
oct | 1625770732433 |
9 | 383021345248 |
10 | 123210020123 |
11 | 48286931813 |
12 | 1ba66952b8b |
13 | b807253968 |
14 | 5d6b7bcb91 |
15 | 3311bd2968 |
hex | 1cafe3b51b |
123210020123 has 4 divisors (see below), whose sum is σ = 123762531648. Its totient is φ = 122657508600.
The previous prime is 123210020099. The next prime is 123210020179. The reversal of 123210020123 is 321020012321.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 321020012321 = 494051 ⋅649771.
It is a cyclic number.
It is not a de Polignac number, because 123210020123 - 210 = 123210019099 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (123210020023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 276255428 + ... + 276255873.
It is an arithmetic number, because the mean of its divisors is an integer number (30940632912).
Almost surely, 2123210020123 is an apocalyptic number.
123210020123 is a deficient number, since it is larger than the sum of its proper divisors (552511525).
123210020123 is an equidigital number, since it uses as much as digits as its factorization.
123210020123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 552511524.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 123210020123 its reverse (321020012321), we get a palindrome (444230032444).
The spelling of 123210020123 in words is "one hundred twenty-three billion, two hundred ten million, twenty thousand, one hundred twenty-three".
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