1232143301143 has 4 divisors (see below), whose sum is σ = 1232163511488. Its totient is φ = 1232123090800.

The previous prime is 1232143301141. The next prime is 1232143301153. The reversal of 1232143301143 is 3411033412321.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1232143301143 - 2¹ = 1232143301141 is a prime.

It is a super-2 number, since 2×1232143301143² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1232143301141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10013446 + ... + 10135747.

It is an arithmetic number, because the mean of its divisors is an integer number (308040877872).

Almost surely, 2^{1232143301143} is an apocalyptic number.

1232143301143 is a deficient number, since it is larger than the sum of its proper divisors (20210345).

1232143301143 is an equidigital number, since it uses as much as digits as its factorization.

1232143301143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20210344.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1232143301143 its reverse (3411033412321), we get a palindrome (4643176713464).

The spelling of 1232143301143 in words is "one trillion, two hundred thirty-two billion, one hundred forty-three million, three hundred one thousand, one hundred forty-three".