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12324132017 is a prime number
BaseRepresentation
bin10110111101001001…
…10101010010110001
31011210220000202212222
423132210311102301
5200214434211032
65354524530425
7614255252021
oct133644652261
934726022788
1012324132017
11525471887a
12247b3b0a15
131215361712
1484cab3a81
154c1e49a12
hex2de9354b1

12324132017 has 2 divisors, whose sum is σ = 12324132018. Its totient is φ = 12324132016.

The previous prime is 12324131999. The next prime is 12324132019. The reversal of 12324132017 is 71023142321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10665932176 + 1658199841 = 103276^2 + 40721^2 .

It is an emirp because it is prime and its reverse (71023142321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12324132017 - 216 = 12324066481 is a prime.

Together with 12324132019, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12324132019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6162066008 + 6162066009.

It is an arithmetic number, because the mean of its divisors is an integer number (6162066009).

Almost surely, 212324132017 is an apocalyptic number.

It is an amenable number.

12324132017 is a deficient number, since it is larger than the sum of its proper divisors (1).

12324132017 is an equidigital number, since it uses as much as digits as its factorization.

12324132017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 26.

Adding to 12324132017 its reverse (71023142321), we get a palindrome (83347274338).

The spelling of 12324132017 in words is "twelve billion, three hundred twenty-four million, one hundred thirty-two thousand, seventeen".