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12328549504877 is a prime number
BaseRepresentation
bin1011001101100111011011…
…0100000101011101101101
31121122121010210221020200002
42303121312310011131231
53103442332133124002
642115354002114045
72411464643512064
oct263316664053555
947577123836602
1012328549504877
113a23565877731
12147143234b925
136b5767235238
143089c26711db
15165a61bdc002
hexb3676d0576d

12328549504877 has 2 divisors, whose sum is σ = 12328549504878. Its totient is φ = 12328549504876.

The previous prime is 12328549504787. The next prime is 12328549504879. The reversal of 12328549504877 is 77840594582321.

Together with previous prime (12328549504787) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11134274281636 + 1194275223241 = 3336806^2 + 1092829^2 .

It is a cyclic number.

It is not a de Polignac number, because 12328549504877 - 218 = 12328549242733 is a prime.

Together with 12328549504879, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12328549504879) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6164274752438 + 6164274752439.

It is an arithmetic number, because the mean of its divisors is an integer number (6164274752439).

Almost surely, 212328549504877 is an apocalyptic number.

It is an amenable number.

12328549504877 is a deficient number, since it is larger than the sum of its proper divisors (1).

12328549504877 is an equidigital number, since it uses as much as digits as its factorization.

12328549504877 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 135475200, while the sum is 65.

The spelling of 12328549504877 in words is "twelve trillion, three hundred twenty-eight billion, five hundred forty-nine million, five hundred four thousand, eight hundred seventy-seven".