Base | Representation |
---|---|
bin | 10001111100010100101… |
… | …001110111001010101111 |
3 | 11100212121001001010102221 |
4 | 101330110221313022233 |
5 | 130200142021212033 |
6 | 2342233334500211 |
7 | 155036641124515 |
oct | 21742451671257 |
9 | 4325531033387 |
10 | 1233002132143 |
11 | 435a05617471 |
12 | 17ab69b04667 |
13 | 8c36b92c952 |
14 | 4396b5724b5 |
15 | 2211717a12d |
hex | 11f14a772af |
1233002132143 has 4 divisors (see below), whose sum is σ = 1238161137120. Its totient is φ = 1227843127168.
The previous prime is 1233002132107. The next prime is 1233002132147. The reversal of 1233002132143 is 3412312003321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1233002132143 - 29 = 1233002131631 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1233002132147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2579502130 + ... + 2579502607.
It is an arithmetic number, because the mean of its divisors is an integer number (309540284280).
Almost surely, 21233002132143 is an apocalyptic number.
1233002132143 is a deficient number, since it is larger than the sum of its proper divisors (5159004977).
1233002132143 is an equidigital number, since it uses as much as digits as its factorization.
1233002132143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5159004976.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 1233002132143 its reverse (3412312003321), we get a palindrome (4645314135464).
The spelling of 1233002132143 in words is "one trillion, two hundred thirty-three billion, two million, one hundred thirty-two thousand, one hundred forty-three".
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