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12330120130020 = 223257111153771569
BaseRepresentation
bin1011001101101101010001…
…1011100010110111100100
31121122202012021100021022200
42303123110123202313210
53104004041223130040
642120213510054500
72411551604556120
oct263332433426744
947582167307280
1012330120130020
113a241a1405640
1214717b034a430
136b5957754724
14308ad10ba580
15165b04a37630
hexb36d46e2de4

12330120130020 has 288 divisors, whose sum is σ = 46670775540480. Its totient is φ = 2559877447680.

The previous prime is 12330120129959. The next prime is 12330120130043. The reversal of 12330120130020 is 2003102103321.

12330120130020 is a `hidden beast` number, since 1 + 2 + 330 + 12 + 0 + 1 + 300 + 20 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 12330120129975 and 12330120130002.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 15594796 + ... + 16366364.

It is an arithmetic number, because the mean of its divisors is an integer number (162051303960).

Almost surely, 212330120130020 is an apocalyptic number.

12330120130020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12330120130020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (23335387770240).

12330120130020 is an abundant number, since it is smaller than the sum of its proper divisors (34340655410460).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12330120130020 is a wasteful number, since it uses less digits than its factorization.

12330120130020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 772755 (or 772750 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 12330120130020 its reverse (2003102103321), we get a palindrome (14333222233341).

The spelling of 12330120130020 in words is "twelve trillion, three hundred thirty billion, one hundred twenty million, one hundred thirty thousand, twenty".