123311320133 has 2 divisors, whose sum is σ = 123311320134. Its totient is φ = 123311320132.

The previous prime is 123311320091. The next prime is 123311320141. The reversal of 123311320133 is 331023113321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121952513089 + 1358807044 = 349217^2 + 36862^2 .

It is an emirp because it is prime and its reverse (331023113321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 123311320133 - 2⁸ = 123311319877 is a prime.

It is a super-2 number, since 2×123311320133² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 123311320099 and 123311320108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123311320163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61655660066 + 61655660067.

It is an arithmetic number, because the mean of its divisors is an integer number (61655660067).

Almost surely, 2^123311320133 is an apocalyptic number.

It is an amenable number.

123311320133 is a deficient number, since it is larger than the sum of its proper divisors (1).

123311320133 is an equidigital number, since it uses as much as digits as its factorization.

123311320133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 123311320133 its reverse (331023113321), we get a palindrome (454334433454).

The spelling of 123311320133 in words is "one hundred twenty-three billion, three hundred eleven million, three hundred twenty thousand, one hundred thirty-three".