Base | Representation |
---|---|
bin | 11100000010011010101000… |
… | …110111000011100110111100 |
3 | 121011121110010120211222000000 |
4 | 130002122220313003212330 |
5 | 112130313113040320043 |
6 | 1114132241024234300 |
7 | 34654644026330310 |
oct | 3402325067034674 |
9 | 534543116758000 |
10 | 123311344073148 |
11 | 36322058011250 |
12 | 119b669376b990 |
13 | 53a629607239a |
14 | 226442d941b40 |
15 | e3c9274102d3 |
hex | 7026a8dc39bc |
123311344073148 has 1344 divisors, whose sum is σ = 442268598804480. Its totient is φ = 29104637990400.
The previous prime is 123311344073123. The next prime is 123311344073149. The reversal of 123311344073148 is 841370443113321.
123311344073148 is a `hidden beast` number, since 1 + 2 + 331 + 134 + 40 + 7 + 3 + 148 = 666.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (123311344073149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 447 ways as a sum of consecutive naturals, for example, 11207060215 + ... + 11207071217.
It is an arithmetic number, because the mean of its divisors is an integer number (329068897920).
Almost surely, 2123311344073148 is an apocalyptic number.
123311344073148 is a gapful number since it is divisible by the number (18) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 123311344073148, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (221134299402240).
123311344073148 is an abundant number, since it is smaller than the sum of its proper divisors (318957254731332).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
123311344073148 is a wasteful number, since it uses less digits than its factorization.
123311344073148 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11170 (or 11153 counting only the distinct ones).
The product of its (nonzero) digits is 580608, while the sum is 45.
Adding to 123311344073148 its reverse (841370443113321), we get a palindrome (964681787186469).
The spelling of 123311344073148 in words is "one hundred twenty-three trillion, three hundred eleven billion, three hundred forty-four million, seventy-three thousand, one hundred forty-eight".
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