Base | Representation |
---|---|
bin | 111001011011000000… |
… | …1110011111001001111 |
3 | 102210021220012001222211 |
4 | 1302312001303321033 |
5 | 4010021112343203 |
6 | 132352121451251 |
7 | 11623545211255 |
oct | 1626601637117 |
9 | 383256161884 |
10 | 123313012303 |
11 | 48329a87318 |
12 | 1ba95340b27 |
13 | b8226a4390 |
14 | 5d7b34c5d5 |
15 | 331ac78c6d |
hex | 1cb6073e4f |
123313012303 has 4 divisors (see below), whose sum is σ = 132798628648. Its totient is φ = 113827395960.
The previous prime is 123313012301. The next prime is 123313012309. The reversal of 123313012303 is 303210313321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 123313012303 - 21 = 123313012301 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (123313012301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4742808153 + ... + 4742808178.
It is an arithmetic number, because the mean of its divisors is an integer number (33199657162).
Almost surely, 2123313012303 is an apocalyptic number.
123313012303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
123313012303 is a deficient number, since it is larger than the sum of its proper divisors (9485616345).
123313012303 is an equidigital number, since it uses as much as digits as its factorization.
123313012303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9485616344.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 123313012303 its reverse (303210313321), we get a palindrome (426523325624).
The spelling of 123313012303 in words is "one hundred twenty-three billion, three hundred thirteen million, twelve thousand, three hundred three".
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