Base | Representation |
---|---|
bin | 11100000010011101011001… |
… | …001011001100111011010111 |
3 | 121011121201202201222112122200 |
4 | 130002131121023030323113 |
5 | 112130340142322103330 |
6 | 1114133450334055543 |
7 | 34655110235452230 |
oct | 3402353113147327 |
9 | 534551681875580 |
10 | 123314302144215 |
11 | 36323335843886 |
12 | 119b717a34a5b3 |
13 | 53a6647b660b0 |
14 | 2264630752087 |
15 | e3ca4be70a60 |
hex | 7027592cced7 |
123314302144215 has 192 divisors, whose sum is σ = 264089927162880. Its totient is φ = 51834551408640.
The previous prime is 123314302144151. The next prime is 123314302144277. The reversal of 123314302144215 is 512441203413321.
123314302144215 is a `hidden beast` number, since 1 + 2 + 3 + 3 + 1 + 430 + 2 + 1 + 4 + 4 + 215 = 666.
It is not a de Polignac number, because 123314302144215 - 26 = 123314302144151 is a prime.
It is a super-2 number, since 2×1233143021442152 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 123314302144215.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 1617007756 + ... + 1617084014.
It is an arithmetic number, because the mean of its divisors is an integer number (1375468370640).
Almost surely, 2123314302144215 is an apocalyptic number.
123314302144215 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
123314302144215 is an abundant number, since it is smaller than the sum of its proper divisors (140775625018665).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
123314302144215 is a wasteful number, since it uses less digits than its factorization.
123314302144215 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 77814 (or 77811 counting only the distinct ones).
The product of its (nonzero) digits is 69120, while the sum is 36.
Adding to 123314302144215 its reverse (512441203413321), we get a palindrome (635755505557536).
The spelling of 123314302144215 in words is "one hundred twenty-three trillion, three hundred fourteen billion, three hundred two million, one hundred forty-four thousand, two hundred fifteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.064 sec. • engine limits •