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123315302540077 is a prime number
BaseRepresentation
bin11100000010011110010100…
…110011011010001100101101
3121011121211100110101220210021
4130002132110303122030231
5112130344214422240302
61114134133512042141
734655144103622234
oct3402362463321455
9534554313356707
10123315302540077
11363237a950801a
12119b73b9393351
1353a67771b14cb
1422646c7563b1b
15e3caa9bce437
hex702794cda32d

123315302540077 has 2 divisors, whose sum is σ = 123315302540078. Its totient is φ = 123315302540076.

The previous prime is 123315302540039. The next prime is 123315302540119. The reversal of 123315302540077 is 770045203513321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 93864590763876 + 29450711776201 = 9688374^2 + 5426851^2 .

It is a cyclic number.

It is not a de Polignac number, because 123315302540077 - 227 = 123315168322349 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123315302543077) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61657651270038 + 61657651270039.

It is an arithmetic number, because the mean of its divisors is an integer number (61657651270039).

Almost surely, 2123315302540077 is an apocalyptic number.

It is an amenable number.

123315302540077 is a deficient number, since it is larger than the sum of its proper divisors (1).

123315302540077 is an equidigital number, since it uses as much as digits as its factorization.

123315302540077 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 529200, while the sum is 43.

The spelling of 123315302540077 in words is "one hundred twenty-three trillion, three hundred fifteen billion, three hundred two million, five hundred forty thousand, seventy-seven".