1233335013133 has 2 divisors, whose sum is σ = 1233335013134. Its totient is φ = 1233335013132.

The previous prime is 1233335013091. The next prime is 1233335013137. The reversal of 1233335013133 is 3313105333321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 877019139049 + 356315874084 = 936493^2 + 596922^2 .

It is a cyclic number.

It is not a de Polignac number, because 1233335013133 - 2¹⁷ = 1233334882061 is a prime.

It is a super-2 number, since 2×1233335013133² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1233335013095 and 1233335013104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1233335013137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616667506566 + 616667506567.

It is an arithmetic number, because the mean of its divisors is an integer number (616667506567).

Almost surely, 2^{1233335013133} is an apocalyptic number.

It is an amenable number.

1233335013133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1233335013133 is an equidigital number, since it uses as much as digits as its factorization.

1233335013133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21870, while the sum is 31.

The spelling of 1233335013133 in words is "one trillion, two hundred thirty-three billion, three hundred thirty-five million, thirteen thousand, one hundred thirty-three".