123334020031 has 4 divisors (see below), whose sum is σ = 128696368752. Its totient is φ = 117971671312.

The previous prime is 123334020013. The next prime is 123334020083. The reversal of 123334020031 is 130020433321.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 123334020031 - 2⁵ = 123334019999 is a prime.

It is a super-2 number, since 2×123334020031² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 123334019984 and 123334020011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (123334020091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2681174326 + ... + 2681174371.

It is an arithmetic number, because the mean of its divisors is an integer number (32174092188).

Almost surely, 2^123334020031 is an apocalyptic number.

123334020031 is a deficient number, since it is larger than the sum of its proper divisors (5362348721).

123334020031 is an equidigital number, since it uses as much as digits as its factorization.

123334020031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5362348720.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 123334020031 its reverse (130020433321), we get a palindrome (253354453352).

The spelling of 123334020031 in words is "one hundred twenty-three billion, three hundred thirty-four million, twenty thousand, thirty-one".