Base | Representation |
---|---|
bin | 10001111100101101000… |
… | …101011001111000011111 |
3 | 11100220122121021211212012 |
4 | 101330231011121320133 |
5 | 130202011433133112 |
6 | 2342342135501435 |
7 | 155053046030351 |
oct | 21745505317037 |
9 | 4326577254765 |
10 | 1233412005407 |
11 | 4360a5a162aa |
12 | 17b06322787b |
13 | 8c40581a1ca |
14 | 439a9b870d1 |
15 | 2213d13e022 |
hex | 11f2d159e1f |
1233412005407 has 2 divisors, whose sum is σ = 1233412005408. Its totient is φ = 1233412005406.
The previous prime is 1233412005373. The next prime is 1233412005431. The reversal of 1233412005407 is 7045002143321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1233412005407 - 214 = 1233411989023 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1233412005907) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616706002703 + 616706002704.
It is an arithmetic number, because the mean of its divisors is an integer number (616706002704).
Almost surely, 21233412005407 is an apocalyptic number.
1233412005407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1233412005407 is an equidigital number, since it uses as much as digits as its factorization.
1233412005407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 32.
Adding to 1233412005407 its reverse (7045002143321), we get a palindrome (8278414148728).
The spelling of 1233412005407 in words is "one trillion, two hundred thirty-three billion, four hundred twelve million, five thousand, four hundred seven".
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