Base | Representation |
---|---|
bin | 1011001101111101101110… |
… | …0001100011110000101111 |
3 | 1121200011120220000220111211 |
4 | 2303133123201203300233 |
5 | 3104042111213124401 |
6 | 42122223505055251 |
7 | 2412066153040111 |
oct | 263373341436057 |
9 | 47604526026454 |
10 | 12334534114351 |
11 | 3a26056a46379 |
12 | 1472622627527 |
13 | 6b61ac072987 |
14 | 308dcd3d53b1 |
15 | 165cb22d4951 |
hex | b37db863c2f |
12334534114351 has 2 divisors, whose sum is σ = 12334534114352. Its totient is φ = 12334534114350.
The previous prime is 12334534114313. The next prime is 12334534114391. The reversal of 12334534114351 is 15341143543321.
It is an a-pointer prime, because the next prime (12334534114391) can be obtained adding 12334534114351 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12334534114351 - 241 = 10135510858799 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12334534114391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6167267057175 + 6167267057176.
It is an arithmetic number, because the mean of its divisors is an integer number (6167267057176).
Almost surely, 212334534114351 is an apocalyptic number.
12334534114351 is a deficient number, since it is larger than the sum of its proper divisors (1).
12334534114351 is an equidigital number, since it uses as much as digits as its factorization.
12334534114351 is an evil number, because the sum of its binary digits is even.
The product of its digits is 259200, while the sum is 40.
Adding to 12334534114351 its reverse (15341143543321), we get a palindrome (27675677657672).
The spelling of 12334534114351 in words is "twelve trillion, three hundred thirty-four billion, five hundred thirty-four million, one hundred fourteen thousand, three hundred fifty-one".
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