Base | Representation |
---|---|
bin | 10110111110011111… |
… | …11110010110110111 |
3 | 1011211200022100100121 |
4 | 23133033332112313 |
5 | 200230333110320 |
6 | 5400011152411 |
7 | 614453343550 |
oct | 133717762667 |
9 | 34750270317 |
10 | 12335441335 |
11 | 5260042718 |
12 | 2483145707 |
13 | 12177c1219 |
14 | 8503b9327 |
15 | 4c2e308aa |
hex | 2df3fe5b7 |
12335441335 has 8 divisors (see below), whose sum is σ = 16917176736. Its totient is φ = 8458588320.
The previous prime is 12335441309. The next prime is 12335441369. The reversal of 12335441335 is 53314453321.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12335441335 - 25 = 12335441303 is a prime.
It is a super-2 number, since 2×123354413352 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 12335441335.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 176220556 + ... + 176220625.
It is an arithmetic number, because the mean of its divisors is an integer number (2114647092).
Almost surely, 212335441335 is an apocalyptic number.
12335441335 is a deficient number, since it is larger than the sum of its proper divisors (4581735401).
12335441335 is an equidigital number, since it uses as much as digits as its factorization.
12335441335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 352441193.
The product of its digits is 64800, while the sum is 34.
Adding to 12335441335 its reverse (53314453321), we get a palindrome (65649894656).
The spelling of 12335441335 in words is "twelve billion, three hundred thirty-five million, four hundred forty-one thousand, three hundred thirty-five".
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