123402000131103 has 4 divisors (see below), whose sum is σ = 164536000174808. Its totient is φ = 82268000087400.

The previous prime is 123402000130993. The next prime is 123402000131107. The reversal of 123402000131103 is 301131000204321.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 123402000131103 - 2¹⁷ = 123402000000031 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 123402000131103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (123402000131107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20567000021848 + ... + 20567000021853.

It is an arithmetic number, because the mean of its divisors is an integer number (41134000043702).

Almost surely, 2^{123402000131103} is an apocalyptic number.

123402000131103 is a deficient number, since it is larger than the sum of its proper divisors (41134000043705).

123402000131103 is an equidigital number, since it uses as much as digits as its factorization.

123402000131103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41134000043704.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 123402000131103 its reverse (301131000204321), we get a palindrome (424533000335424).

The spelling of 123402000131103 in words is "one hundred twenty-three trillion, four hundred two billion, one hundred thirty-one thousand, one hundred three".