Base | Representation |
---|---|
bin | 10001111101010010100… |
… | …100111100011101011011 |
3 | 11100222021102220122001112 |
4 | 101331102210330131123 |
5 | 130204304000433431 |
6 | 2342524410010535 |
7 | 155104454454623 |
oct | 21752244743533 |
9 | 4328242818045 |
10 | 1234041030491 |
11 | 436398a99145 |
12 | 17b1b9a16a4b |
13 | 8c4a5c390b9 |
14 | 43a29527883 |
15 | 22178491c2b |
hex | 11f5293c75b |
1234041030491 has 2 divisors, whose sum is σ = 1234041030492. Its totient is φ = 1234041030490.
The previous prime is 1234041030413. The next prime is 1234041030493. The reversal of 1234041030491 is 1940301404321.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1234041030491 is a prime.
Together with 1234041030493, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1234041030493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 617020515245 + 617020515246.
It is an arithmetic number, because the mean of its divisors is an integer number (617020515246).
Almost surely, 21234041030491 is an apocalyptic number.
1234041030491 is a deficient number, since it is larger than the sum of its proper divisors (1).
1234041030491 is an equidigital number, since it uses as much as digits as its factorization.
1234041030491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 32.
The spelling of 1234041030491 in words is "one trillion, two hundred thirty-four billion, forty-one million, thirty thousand, four hundred ninety-one".
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