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1234041030491 is a prime number
BaseRepresentation
bin10001111101010010100…
…100111100011101011011
311100222021102220122001112
4101331102210330131123
5130204304000433431
62342524410010535
7155104454454623
oct21752244743533
94328242818045
101234041030491
11436398a99145
1217b1b9a16a4b
138c4a5c390b9
1443a29527883
1522178491c2b
hex11f5293c75b

1234041030491 has 2 divisors, whose sum is σ = 1234041030492. Its totient is φ = 1234041030490.

The previous prime is 1234041030413. The next prime is 1234041030493. The reversal of 1234041030491 is 1940301404321.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1234041030491 is a prime.

Together with 1234041030493, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1234041030493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 617020515245 + 617020515246.

It is an arithmetic number, because the mean of its divisors is an integer number (617020515246).

Almost surely, 21234041030491 is an apocalyptic number.

1234041030491 is a deficient number, since it is larger than the sum of its proper divisors (1).

1234041030491 is an equidigital number, since it uses as much as digits as its factorization.

1234041030491 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 32.

The spelling of 1234041030491 in words is "one trillion, two hundred thirty-four billion, forty-one million, thirty thousand, four hundred ninety-one".