12341412133 has 4 divisors (see below), whose sum is σ = 12990960160. Its totient is φ = 11691864108.

The previous prime is 12341412121. The next prime is 12341412199. The reversal of 12341412133 is 33121414321.

12341412133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33121414321 = 47 ⋅704710943.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12341412133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12341412098 and 12341412107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12341412103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 324773985 + ... + 324774022.

It is an arithmetic number, because the mean of its divisors is an integer number (3247740040).

Almost surely, 2^12341412133 is an apocalyptic number.

It is an amenable number.

12341412133 is a deficient number, since it is larger than the sum of its proper divisors (649548027).

12341412133 is an equidigital number, since it uses as much as digits as its factorization.

12341412133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 649548026.

The product of its digits is 1728, while the sum is 25.

Adding to 12341412133 its reverse (33121414321), we get a palindrome (45462826454).

The spelling of 12341412133 in words is "twelve billion, three hundred forty-one million, four hundred twelve thousand, one hundred thirty-three".