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123441402013 is a prime number
BaseRepresentation
bin111001011110110101…
…1100101000010011101
3102210121211202221120021
41302331223211002131
54010301444331023
6132412545352141
711626664414266
oct1627553450235
9383554687507
10123441402013
11483954a9416
121bb10338651
13b843177c17
145d9040d96d
15332718a35d
hex1cbdae509d

123441402013 has 2 divisors, whose sum is σ = 123441402014. Its totient is φ = 123441402012.

The previous prime is 123441402011. The next prime is 123441402037. The reversal of 123441402013 is 310204144321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 92113464004 + 31327938009 = 303502^2 + 176997^2 .

It is an emirp because it is prime and its reverse (310204144321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 123441402013 - 21 = 123441402011 is a prime.

Together with 123441402011, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123441402011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61720701006 + 61720701007.

It is an arithmetic number, because the mean of its divisors is an integer number (61720701007).

Almost surely, 2123441402013 is an apocalyptic number.

It is an amenable number.

123441402013 is a deficient number, since it is larger than the sum of its proper divisors (1).

123441402013 is an equidigital number, since it uses as much as digits as its factorization.

123441402013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 123441402013 its reverse (310204144321), we get a palindrome (433645546334).

The spelling of 123441402013 in words is "one hundred twenty-three billion, four hundred forty-one million, four hundred two thousand, thirteen".