Base | Representation |
---|---|
bin | 111001011110110101… |
… | …1100101000010011101 |
3 | 102210121211202221120021 |
4 | 1302331223211002131 |
5 | 4010301444331023 |
6 | 132412545352141 |
7 | 11626664414266 |
oct | 1627553450235 |
9 | 383554687507 |
10 | 123441402013 |
11 | 483954a9416 |
12 | 1bb10338651 |
13 | b843177c17 |
14 | 5d9040d96d |
15 | 332718a35d |
hex | 1cbdae509d |
123441402013 has 2 divisors, whose sum is σ = 123441402014. Its totient is φ = 123441402012.
The previous prime is 123441402011. The next prime is 123441402037. The reversal of 123441402013 is 310204144321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 92113464004 + 31327938009 = 303502^2 + 176997^2 .
It is an emirp because it is prime and its reverse (310204144321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 123441402013 - 21 = 123441402011 is a prime.
Together with 123441402011, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123441402011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61720701006 + 61720701007.
It is an arithmetic number, because the mean of its divisors is an integer number (61720701007).
Almost surely, 2123441402013 is an apocalyptic number.
It is an amenable number.
123441402013 is a deficient number, since it is larger than the sum of its proper divisors (1).
123441402013 is an equidigital number, since it uses as much as digits as its factorization.
123441402013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 123441402013 its reverse (310204144321), we get a palindrome (433645546334).
The spelling of 123441402013 in words is "one hundred twenty-three billion, four hundred forty-one million, four hundred two thousand, thirteen".
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