Base | Representation |
---|---|
bin | 111001011111101110… |
… | …0011111011101111111 |
3 | 102210200220110202101111 |
4 | 1302333130133131333 |
5 | 4010332034021341 |
6 | 132415524022451 |
7 | 11630504124136 |
oct | 1627734373577 |
9 | 383626422344 |
10 | 123471001471 |
11 | 48400185984 |
12 | 1bb1a231a27 |
13 | b84933c7ac |
14 | 5d9431691d |
15 | 3329a85681 |
hex | 1cbf71f77f |
123471001471 has 2 divisors, whose sum is σ = 123471001472. Its totient is φ = 123471001470.
The previous prime is 123471001469. The next prime is 123471001543. The reversal of 123471001471 is 174100174321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 123471001471 - 21 = 123471001469 is a prime.
It is a super-3 number, since 3×1234710014713 (a number of 34 digits) contains 333 as substring.
Together with 123471001469, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123471901471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61735500735 + 61735500736.
It is an arithmetic number, because the mean of its divisors is an integer number (61735500736).
Almost surely, 2123471001471 is an apocalyptic number.
123471001471 is a deficient number, since it is larger than the sum of its proper divisors (1).
123471001471 is an equidigital number, since it uses as much as digits as its factorization.
123471001471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4704, while the sum is 31.
Adding to 123471001471 its reverse (174100174321), we get a palindrome (297571175792).
The spelling of 123471001471 in words is "one hundred twenty-three billion, four hundred seventy-one million, one thousand, four hundred seventy-one".
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