Base | Representation |
---|---|
bin | 111001100001111000… |
… | …0011101000001111110 |
3 | 102210212221121002121220 |
4 | 1303003300131001332 |
5 | 4011004043440410 |
6 | 132431030334210 |
7 | 11632343043066 |
oct | 1630360350176 |
9 | 383787532556 |
10 | 123543343230 |
11 | 48437aa635a |
12 | 1bb3a4ba366 |
13 | b85b31b178 |
14 | 5d9db883a6 |
15 | 33310c5070 |
hex | 1cc3c1d07e |
123543343230 has 32 divisors (see below), whose sum is σ = 301529520000. Its totient is φ = 32386503072.
The previous prime is 123543343229. The next prime is 123543343267. The reversal of 123543343230 is 32343345321.
It is a junction number, because it is equal to n+sod(n) for n = 123543343191 and 123543343200.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34897480 + ... + 34901019.
It is an arithmetic number, because the mean of its divisors is an integer number (9422797500).
Almost surely, 2123543343230 is an apocalyptic number.
123543343230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
123543343230 is an abundant number, since it is smaller than the sum of its proper divisors (177986176770).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
123543343230 is a wasteful number, since it uses less digits than its factorization.
123543343230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69798568.
The product of its (nonzero) digits is 77760, while the sum is 33.
Adding to 123543343230 its reverse (32343345321), we get a palindrome (155886688551).
The spelling of 123543343230 in words is "one hundred twenty-three billion, five hundred forty-three million, three hundred forty-three thousand, two hundred thirty".
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